(2+v)(2v-3)=0

Solution for (2+v)(2v-3)=0 equation:

(2+v)(2v-3)=0

We add all the numbers together, and all the variables

(v+2)(2v-3)=0

We multiply parentheses ..

(+2v^2-3v+4v-6)=0

We get rid of parentheses

2v^2-3v+4v-6=0

We add all the numbers together, and all the variables

2v^2+v-6=0

a = 2; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·2·(-6)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-7}{2*2}=\frac{-8}{4}
=-2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+7}{2*2}=\frac{6}{4}
=1+1/2
$