(2+i)z=1-3i

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Solution for (2+i)z=1-3i equation:


Simplifying
(2 + i) * z = 1 + -3i

Reorder the terms for easier multiplication:
z(2 + i) = 1 + -3i
(2 * z + i * z) = 1 + -3i

Reorder the terms:
(iz + 2z) = 1 + -3i
(iz + 2z) = 1 + -3i

Solving
iz + 2z = 1 + -3i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '3i' to each side of the equation.
iz + 3i + 2z = 1 + -3i + 3i

Reorder the terms:
3i + iz + 2z = 1 + -3i + 3i

Combine like terms: -3i + 3i = 0
3i + iz + 2z = 1 + 0
3i + iz + 2z = 1

Add '-2z' to each side of the equation.
3i + iz + 2z + -2z = 1 + -2z

Combine like terms: 2z + -2z = 0
3i + iz + 0 = 1 + -2z
3i + iz = 1 + -2z

Reorder the terms:
-1 + 3i + iz + 2z = 1 + -2z + -1 + 2z

Reorder the terms:
-1 + 3i + iz + 2z = 1 + -1 + -2z + 2z

Combine like terms: 1 + -1 = 0
-1 + 3i + iz + 2z = 0 + -2z + 2z
-1 + 3i + iz + 2z = -2z + 2z

Combine like terms: -2z + 2z = 0
-1 + 3i + iz + 2z = 0

The solution to this equation could not be determined.

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