(2+i)z-3+2i=0

Solution for (2+i)z-3+2i=0 equation:

Simplifying
(2 + i) * z + -3 + 2i = 0

Reorder the terms for easier multiplication:
z(2 + i) + -3 + 2i = 0
(2 * z + i * z) + -3 + 2i = 0

Reorder the terms:
(iz + 2z) + -3 + 2i = 0
(iz + 2z) + -3 + 2i = 0

Reorder the terms:
-3 + 2i + iz + 2z = 0

Solving
-3 + 2i + iz + 2z = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 2i + iz + 3 + 2z = 0 + 3

Reorder the terms:
-3 + 3 + 2i + iz + 2z = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 2i + iz + 2z = 0 + 3
2i + iz + 2z = 0 + 3

Combine like terms: 0 + 3 = 3
2i + iz + 2z = 3

Add '-2z' to each side of the equation.
2i + iz + 2z + -2z = 3 + -2z

Combine like terms: 2z + -2z = 0
2i + iz + 0 = 3 + -2z
2i + iz = 3 + -2z

Reorder the terms:
-3 + 2i + iz + 2z = 3 + -2z + -3 + 2z

Reorder the terms:
-3 + 2i + iz + 2z = 3 + -3 + -2z + 2z

Combine like terms: 3 + -3 = 0
-3 + 2i + iz + 2z = 0 + -2z + 2z
-3 + 2i + iz + 2z = -2z + 2z

Combine like terms: -2z + 2z = 0
-3 + 2i + iz + 2z = 0

The solution to this equation could not be determined.