(2+i)(4+3i)=

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Solution for (2+i)(4+3i)= equation:


Simplifying
(2 + i)(4 + 3i) = 0

Multiply (2 + i) * (4 + 3i)
(2(4 + 3i) + i(4 + 3i)) = 0
((4 * 2 + 3i * 2) + i(4 + 3i)) = 0
((8 + 6i) + i(4 + 3i)) = 0
(8 + 6i + (4 * i + 3i * i)) = 0
(8 + 6i + (4i + 3i2)) = 0

Combine like terms: 6i + 4i = 10i
(8 + 10i + 3i2) = 0

Solving
8 + 10i + 3i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(2 + i)(4 + 3i) = 0

Subproblem 1

Set the factor '(2 + i)' equal to zero and attempt to solve: Simplifying 2 + i = 0 Solving 2 + i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + i = 0 + -2 i = 0 + -2 Combine like terms: 0 + -2 = -2 i = -2 Simplifying i = -2

Subproblem 2

Set the factor '(4 + 3i)' equal to zero and attempt to solve: Simplifying 4 + 3i = 0 Solving 4 + 3i = 0 Move all terms containing i to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + 3i = 0 + -4 Combine like terms: 4 + -4 = 0 0 + 3i = 0 + -4 3i = 0 + -4 Combine like terms: 0 + -4 = -4 3i = -4 Divide each side by '3'. i = -1.333333333 Simplifying i = -1.333333333

Solution

i = {-2, -1.333333333}

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