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(2+3i)=(1+2i)
We move all terms to the left:
(2+3i)-((1+2i))=0
We add all the numbers together, and all the variables
(3i+2)-((2i+1))=0
We get rid of parentheses
3i-((2i+1))+2=0
We calculate terms in parentheses: -((2i+1)), so:We get rid of parentheses
(2i+1)
We get rid of parentheses
2i+1
Back to the equation:
-(2i+1)
3i-2i-1+2=0
We add all the numbers together, and all the variables
i+1=0
We move all terms containing i to the left, all other terms to the right
i=-1
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