(2+3i)(4+2i)=

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Solution for (2+3i)(4+2i)= equation:


Simplifying
(2 + 3i)(4 + 2i) = 0

Multiply (2 + 3i) * (4 + 2i)
(2(4 + 2i) + 3i * (4 + 2i)) = 0
((4 * 2 + 2i * 2) + 3i * (4 + 2i)) = 0
((8 + 4i) + 3i * (4 + 2i)) = 0
(8 + 4i + (4 * 3i + 2i * 3i)) = 0
(8 + 4i + (12i + 6i2)) = 0

Combine like terms: 4i + 12i = 16i
(8 + 16i + 6i2) = 0

Solving
8 + 16i + 6i2 = 0

Solving for variable 'i'.

Factor out the Greatest Common Factor (GCF), '2'.
2(4 + 8i + 3i2) = 0

Factor a trinomial.
2((2 + i)(2 + 3i)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(2 + i)' equal to zero and attempt to solve: Simplifying 2 + i = 0 Solving 2 + i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + i = 0 + -2 i = 0 + -2 Combine like terms: 0 + -2 = -2 i = -2 Simplifying i = -2

Subproblem 2

Set the factor '(2 + 3i)' equal to zero and attempt to solve: Simplifying 2 + 3i = 0 Solving 2 + 3i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 3i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 3i = 0 + -2 3i = 0 + -2 Combine like terms: 0 + -2 = -2 3i = -2 Divide each side by '3'. i = -0.6666666667 Simplifying i = -0.6666666667

Solution

i = {-2, -0.6666666667}

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