(2)c-7=(c-7)+(3c-33)

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Solution for (2)c-7=(c-7)+(3c-33) equation: 



(2)c-7=(c-7)+(3c-33)

We move all terms to the left:

(2)c-7-((c-7)+(3c-33))=0



We calculate terms in parentheses: -((c-7)+(3c-33)), so:

(c-7)+(3c-33)

We get rid of parentheses

c+3c-7-33

We add all the numbers together, and all the variables

4c-40

Back to the equation:

-(4c-40)



We get rid of parentheses

2c-4c+40-7=0

We add all the numbers together, and all the variables

-2c+33=0

We move all terms containing c to the left, all other terms to the right

-2c=-33

c=-33/-2

c=16+1/2

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