(2)=-x2+5(2)+2.5

Solution for (2)=-x2+5(2)+2.5 equation:

(2)=-x2+5(2)+2.5

We move all terms to the left:

(2)-(-x2+5(2)+2.5)=0

We add all the numbers together, and all the variables

-(-1x^2+52+2.5)+2=0

We get rid of parentheses

1x^2-52-2.5+2=0

We add all the numbers together, and all the variables

x^2-52.5=0

a = 1; b = 0; c = -52.5;
Δ = b2-4ac
Δ = 02-4·1·(-52.5)
Δ = 210
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{210}}{2*1}=\frac{0-\sqrt{210}}{2}
=-\frac{\sqrt{}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{210}}{2*1}=\frac{0+\sqrt{210}}{2}
=\frac{\sqrt{}}{2}
$