(2)=-6/5(-4)+b

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Solution for (2)=-6/5(-4)+b equation: 



(2)=-6/5(-4)+b

We move all terms to the left:

(2)-(-6/5(-4)+b)=0



Domain of the equation: 5(-4)+b)!=0

b∈R



We multiply all the terms by the denominator


-(-6+2*5(-4)+b)=0



We calculate terms in parentheses: -(-6+2*5(-4)+b), so:

-6+2*5(-4)+b

determiningTheFunctionDomain
b-6+2*5(-4)

We add all the numbers together, and all the variables

b-46

Back to the equation:

-(b-46)



We get rid of parentheses

-b+46=0

We add all the numbers together, and all the variables

-1b+46=0

We move all terms containing b to the left, all other terms to the right

-b=-46

b=-46/-1

b=+46

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