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(2)3x+10=(2)x
We move all terms to the left:
(2)3x+10-((2)x)=0
determiningTheFunctionDomain 23x-2x+10=0
We add all the numbers together, and all the variables
21x+10=0
We move all terms containing x to the left, all other terms to the right
21x=-10
x=-10/21
x=-10/21
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