(2)/(5s+15)=(1)/(5s)

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Solution for (2)/(5s+15)=(1)/(5s) equation:



(2)/(5s+15)=(1)/(5s)
We move all terms to the left:
(2)/(5s+15)-((1)/(5s))=0
Domain of the equation: (5s+15)!=0
We move all terms containing s to the left, all other terms to the right
5s!=-15
s!=-15/5
s!=-3
s∈R
Domain of the equation: 5s)!=0
s!=0/1
s!=0
s∈R
We add all the numbers together, and all the variables
2/(5s+15)-(+1/5s)=0
We get rid of parentheses
2/(5s+15)-1/5s=0
We calculate fractions
10s/(25s^2+75s)+(-1*(5s+15))/(25s^2+75s)=0
We calculate terms in parentheses: +(-1*(5s+15))/(25s^2+75s), so:
-1*(5s+15))/(25s^2+75s
We add all the numbers together, and all the variables
75s-1*(5s+15))/(25s^2
We multiply all the terms by the denominator
75s*(25s^2-1*(5s+15))
Back to the equation:
+(75s*(25s^2-1*(5s+15)))
We multiply all the terms by the denominator
10s+((75s*(25s^2-1*(5s+15))))*(25s^2+75s)=0
We calculate terms in parentheses: +((75s*(25s^2-1*(5s+15))))*(25s^2+75s), so:
(75s*(25s^2-1*(5s+15))))*(25s^2+75s
We add all the numbers together, and all the variables
75s+(75s*(25s^2-1*(5s+15))))*(25s^2
Back to the equation:
+(75s+(75s*(25s^2-1*(5s+15))))*(25s^2)

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