(2(x-3)x0.5)-0.333=0

Solution for (2(x-3)x0.5)-0.333=0 equation:

(2(x-3)x0.5)-0.333=0


We calculate terms in parentheses: +(2(x-3)x0.5), so:

2(x-3)x0.5

We multiply parentheses

2x^2-6x

Back to the equation:

+(2x^2-6x)


We get rid of parentheses

2x^2-6x-0.333=0

a = 2; b = -6; c = -0.333;
Δ = b2-4ac
Δ = -62-4·2·(-0.333)
Δ = 38.664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{38.664}}{2*2}=\frac{6-\sqrt{38.664}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{38.664}}{2*2}=\frac{6+\sqrt{38.664}}{4}
$