(2(5x-5))=(6x+20)

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Solution for (2(5x-5))=(6x+20) equation: 



(2(5x-5))=(6x+20)

We move all terms to the left:

(2(5x-5))-((6x+20))=0



We calculate terms in parentheses: +(2(5x-5)), so:

2(5x-5)

We multiply parentheses

10x-10

Back to the equation:

+(10x-10)





We calculate terms in parentheses: -((6x+20)), so:

(6x+20)

We get rid of parentheses

6x+20

Back to the equation:

-(6x+20)



We get rid of parentheses

10x-6x-10-20=0

We add all the numbers together, and all the variables

4x-30=0

We move all terms containing x to the left, all other terms to the right

4x=30

x=30/4

x=7+1/2

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