(2(4x-3))/7=2x-6

Solution for (2(4x-3))/7=2x-6 equation:

(2(4x-3))/7=2x-6

We move all terms to the left:

(2(4x-3))/7-(2x-6)=0

We get rid of parentheses

(2(4x-3))/7-2x+6=0

We multiply all the terms by the denominator


(2(4x-3))-2x*7+6*7=0


We calculate terms in parentheses: +(2(4x-3)), so:

2(4x-3)

We multiply parentheses

8x-6

Back to the equation:

+(8x-6)


We add all the numbers together, and all the variables

(8x-6)-2x*7+42=0

Wy multiply elements

(8x-6)-14x+42=0

We get rid of parentheses

8x-14x-6+42=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6