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(2(2x-5))/9=2-5x
We move all terms to the left:
(2(2x-5))/9-(2-5x)=0
We add all the numbers together, and all the variables
(2(2x-5))/9-(-5x+2)=0
We get rid of parentheses
(2(2x-5))/9+5x-2=0
We multiply all the terms by the denominator
(2(2x-5))+5x*9-2*9=0
We calculate terms in parentheses: +(2(2x-5)), so:We add all the numbers together, and all the variables
2(2x-5)
We multiply parentheses
4x-10
Back to the equation:
+(4x-10)
(4x-10)+5x*9-18=0
Wy multiply elements
(4x-10)+45x-18=0
We get rid of parentheses
4x+45x-10-18=0
We add all the numbers together, and all the variables
49x-28=0
We move all terms containing x to the left, all other terms to the right
49x=28
x=28/49
x=4/7
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