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(2(2x+1)=5-2x)
We move all terms to the left:
(2(2x+1)-(5-2x))=0
We add all the numbers together, and all the variables
(2(2x+1)-(-2x+5))=0
We calculate terms in parentheses: +(2(2x+1)-(-2x+5)), so:We get rid of parentheses
2(2x+1)-(-2x+5)
We multiply parentheses
4x-(-2x+5)+2
We get rid of parentheses
4x+2x-5+2
We add all the numbers together, and all the variables
6x-3
Back to the equation:
+(6x-3)
6x-3=0
We move all terms containing x to the left, all other terms to the right
6x=3
x=3/6
x=1/2
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