(2(2x+1)/3)=6

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Solution for (2(2x+1)/3)=6 equation: 



(2(2x+1)/3)=6

We move all terms to the left:

(2(2x+1)/3)-(6)=0

We multiply all the terms by the denominator


(2(2x+1)-6*3)=0



We calculate terms in parentheses: +(2(2x+1)-6*3), so:

2(2x+1)-6*3

We add all the numbers together, and all the variables

2(2x+1)-18

We multiply parentheses

4x+2-18

We add all the numbers together, and all the variables

4x-16

Back to the equation:

+(4x-16)



We get rid of parentheses

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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