(2(2-3x))/(0,01)-(2,5)=(0,02-2x)/(0,02)-(7,5)

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Solution for (2(2-3x))/(0,01)-(2,5)=(0,02-2x)/(0,02)-(7,5) equation: 


x in (-oo:+oo)

(2*(2-(3*x)))/0.01-2.5 = (0.02-(2*x))/0.02-7.5 // - (0.02-(2*x))/0.02-7.5

(2*(2-(3*x)))/0.01-((0.02-(2*x))/0.02)-2.5+7.5 = 0

(2*(2-3*x))/0.01-50*(0.02-2*x)-2.5+7.5 = 0

(2*(2-3*x))/0.01+(-50*0.01*(0.02-2*x))/0.01+(-2.5*0.01)/0.01+(0.01*7.5)/0.01 = 0

2*(2-3*x)-50*0.01*(0.02-2*x)-2.5*0.01+0.01*7.5 = 0

0.075-5*x-0.025+3.99 = 0

0.075-5*x+3.965 = 0

4.04-5*x = 0

(4.04-5*x)/0.01 = 0

(4.04-5*x)/0.01 = 0 // * 0.01

4.04-5*x = 0

4.04-5*x = 0 // - 4.04

-5*x = -4.04 // : -5

x = -4.04/(-5)

x = 0.808

x = 0.808

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