(1x-5)(1x+5)=0

Solution for (1x-5)(1x+5)=0 equation:

Simplifying
(1x + -5)(1x + 5) = 0

Reorder the terms:
(-5 + 1x)(1x + 5) = 0

Reorder the terms:
(-5 + 1x)(5 + 1x) = 0

Multiply (-5 + 1x) * (5 + 1x)
(-5(5 + 1x) + 1x * (5 + 1x)) = 0
((5 * -5 + 1x * -5) + 1x * (5 + 1x)) = 0
((-25 + -5x) + 1x * (5 + 1x)) = 0
(-25 + -5x + (5 * 1x + 1x * 1x)) = 0
(-25 + -5x + (5x + 1x2)) = 0

Combine like terms: -5x + 5x = 0
(-25 + 0 + 1x2) = 0
(-25 + 1x2) = 0

Solving
-25 + 1x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 1x2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 1x2 = 0 + 25
1x2 = 0 + 25

Combine like terms: 0 + 25 = 25
1x2 = 25

Divide each side by '1'.
x2 = 25

Simplifying
x2 = 25

Take the square root of each side:
x = {-5, 5}