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(1x+6+6)+(1x+3)+(1x+3+6)=30
We move all terms to the left:
(1x+6+6)+(1x+3)+(1x+3+6)-(30)=0
We add all the numbers together, and all the variables
(x+12)+(x+3)+(x+9)-30=0
We get rid of parentheses
x+x+x+12+3+9-30=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2
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