(1x+3)(2x+1)=

Solution for (1x+3)(2x+1)= equation:

Simplifying
(1x + 3)(2x + 1) = 0

Reorder the terms:
(3 + 1x)(2x + 1) = 0

Reorder the terms:
(3 + 1x)(1 + 2x) = 0

Multiply (3 + 1x) * (1 + 2x)
(3(1 + 2x) + 1x * (1 + 2x)) = 0
((1 * 3 + 2x * 3) + 1x * (1 + 2x)) = 0
((3 + 6x) + 1x * (1 + 2x)) = 0
(3 + 6x + (1 * 1x + 2x * 1x)) = 0
(3 + 6x + (1x + 2x2)) = 0

Combine like terms: 6x + 1x = 7x
(3 + 7x + 2x2) = 0

Solving
3 + 7x + 2x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(3 + x)(1 + 2x) = 0

Subproblem 1
Set the factor '(3 + x)' equal to zero and attempt to solve:

Simplifying
3 + x = 0

Solving
3 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + x = 0 + -3
x = 0 + -3

Combine like terms: 0 + -3 = -3
x = -3

Simplifying
x = -3
Subproblem 2
Set the factor '(1 + 2x)' equal to zero and attempt to solve:

Simplifying
1 + 2x = 0

Solving
1 + 2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2x = 0 + -1
2x = 0 + -1

Combine like terms: 0 + -1 = -1
2x = -1

Divide each side by '2'.
x = -0.5

Simplifying
x = -0.5
Solution
x = {-3, -0.5}