(1x)+(3y)+(1z)+(2m)=3

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Solution for (1x)+(3y)+(1z)+(2m)=3 equation: 


Simplifying
(1x) + (3y) + (1z) + (2m) = 3

Reorder the terms:
(2m) + (1x) + (3y) + (1z) = 3

Solving
(2m) + (1x) + (3y) + (1z) = 3

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '(-1x)' to each side of the equation.
(2m) + (1x) + (3y) + (-1x) + (1z) = 3 + (-1x)

Reorder the terms:
(2m) + (1x) + (-1x) + (3y) + (1z) = 3 + (-1x)

Combine like terms: (1x) + (-1x) = 0
(2m) + 0 + (3y) + (1z) = 3 + (-1x)
(2m) + (3y) + (1z) = 3 + (-1x)

Add '(-3y)' to each side of the equation.
(2m) + (3y) + (-3y) + (1z) = 3 + (-1x) + (-3y)

Combine like terms: (3y) + (-3y) = 0
(2m) + 0 + (1z) = 3 + (-1x) + (-3y)
(2m) + (1z) = 3 + (-1x) + (-3y)

Add '(-1z)' to each side of the equation.
(2m) + (1z) + (-1z) = 3 + (-1x) + (-3y) + (-1z)

Combine like terms: (1z) + (-1z) = 0
(2m) + 0 = 3 + (-1x) + (-3y) + (-1z)
(2m) = 3 + (-1x) + (-3y) + (-1z)

Divide each side by '2'.
m = 1.5 + (-0.5x) + (-1.5y) + (-0.5z)

Simplifying
m = 1.5 + (-0.5x) + (-1.5y) + (-0.5z)

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