(1x)+(.25x)+(.1x)=x,x0 - solution

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Solution for (1x)+(.25x)+(.1x)=x,x0 equation:


(1x)+(.25x)+(.1x)=x.x^0

We move all terms to the left:

(1x)+(.25x)+(.1x)-(x.x^0)=0

We do not support expression: x^0

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