(19x+3)+(9x+1)+(11x-2)=180

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Solution for (19x+3)+(9x+1)+(11x-2)=180 equation: 



(19x+3)+(9x+1)+(11x-2)=180

We move all terms to the left:

(19x+3)+(9x+1)+(11x-2)-(180)=0

We get rid of parentheses

19x+9x+11x+3+1-2-180=0

We add all the numbers together, and all the variables

39x-178=0

We move all terms containing x to the left, all other terms to the right

39x=178

x=178/39

x=4+22/39

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