(19x+2)+(71x-2)=180

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Solution for (19x+2)+(71x-2)=180 equation: 



(19x+2)+(71x-2)=180

We move all terms to the left:

(19x+2)+(71x-2)-(180)=0

We get rid of parentheses

19x+71x+2-2-180=0

We add all the numbers together, and all the variables

90x-180=0

We move all terms containing x to the left, all other terms to the right

90x=180

x=180/90

x=2

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