(19x+1)=(12x+22)

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Solution for (19x+1)=(12x+22) equation: 



(19x+1)=(12x+22)

We move all terms to the left:

(19x+1)-((12x+22))=0

We get rid of parentheses

19x-((12x+22))+1=0



We calculate terms in parentheses: -((12x+22)), so:

(12x+22)

We get rid of parentheses

12x+22

Back to the equation:

-(12x+22)



We get rid of parentheses

19x-12x-22+1=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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