(19b-6)-6(3b+2)=-5

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Solution for (19b-6)-6(3b+2)=-5 equation: 



(19b-6)-6(3b+2)=-5

We move all terms to the left:

(19b-6)-6(3b+2)-(-5)=0

We add all the numbers together, and all the variables

(19b-6)-6(3b+2)+5=0

We multiply parentheses

(19b-6)-18b-12+5=0

We get rid of parentheses

19b-18b-6-12+5=0

We add all the numbers together, and all the variables

b-13=0

We move all terms containing b to the left, all other terms to the right

b=13

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