(19-x)x-2=-30

Solution for (19-x)x-2=-30 equation:

(19-x)x-2=-30

We move all terms to the left:

(19-x)x-2-(-30)=0

We add all the numbers together, and all the variables

(-1x+19)x-2-(-30)=0

We add all the numbers together, and all the variables

(-1x+19)x+28=0

We multiply parentheses

-1x^2+19x+28=0

a = -1; b = 19; c = +28;
Δ = b2-4ac
Δ = 192-4·(-1)·28
Δ = 473
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{473}}{2*-1}=\frac{-19-\sqrt{473}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{473}}{2*-1}=\frac{-19+\sqrt{473}}{-2}
$