(19-2x)(26-2x)=144

Solution for (19-2x)(26-2x)=144 equation:

(19-2x)(26-2x)=144

We move all terms to the left:

(19-2x)(26-2x)-(144)=0

We add all the numbers together, and all the variables

(-2x+19)(-2x+26)-144=0

We multiply parentheses ..

(+4x^2-52x-38x+494)-144=0

We get rid of parentheses

4x^2-52x-38x+494-144=0

We add all the numbers together, and all the variables

4x^2-90x+350=0

a = 4; b = -90; c = +350;
Δ = b2-4ac
Δ = -902-4·4·350
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-50}{2*4}=\frac{40}{8}
=5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+50}{2*4}=\frac{140}{8}
=17+1/2
$