(19+3x)=(5x-47)

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Solution for (19+3x)=(5x-47) equation: 



(19+3x)=(5x-47)

We move all terms to the left:

(19+3x)-((5x-47))=0

We add all the numbers together, and all the variables

(3x+19)-((5x-47))=0

We get rid of parentheses

3x-((5x-47))+19=0



We calculate terms in parentheses: -((5x-47)), so:

(5x-47)

We get rid of parentheses

5x-47

Back to the equation:

-(5x-47)



We get rid of parentheses

3x-5x+47+19=0

We add all the numbers together, and all the variables

-2x+66=0

We move all terms containing x to the left, all other terms to the right

-2x=-66

x=-66/-2

x=+33

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