(18x-4x)+(10x-8x)=50

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Solution for (18x-4x)+(10x-8x)=50 equation: 



(18x-4x)+(10x-8x)=50

We move all terms to the left:

(18x-4x)+(10x-8x)-(50)=0

We add all the numbers together, and all the variables

(+14x)+(+2x)-50=0

We get rid of parentheses

14x+2x-50=0

We add all the numbers together, and all the variables

16x-50=0

We move all terms containing x to the left, all other terms to the right

16x=50

x=50/16

x=3+1/8

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