(18x+(15/2(x)))=510

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Solution for (18x+(15/2(x)))=510 equation: 



(18x+(15/2(x)))=510

We move all terms to the left:

(18x+(15/2(x)))-(510)=0



Domain of the equation: 2x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(18x+(+15/2x))-510=0

We multiply all the terms by the denominator


(18x+(+15-510*2x))=0



We calculate terms in parentheses: +(18x+(+15-510*2x)), so:

18x+(+15-510*2x)

We add all the numbers together, and all the variables

18x+(-510*2x+15)

We get rid of parentheses

18x-510*2x+15

Wy multiply elements

18x-1020x+15

We add all the numbers together, and all the variables

-1002x+15

Back to the equation:

+(-1002x+15)



We get rid of parentheses

-1002x+15=0

We move all terms containing x to the left, all other terms to the right

-1002x=-15

x=-15/-1002

x=5/334

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