(180-3x)+(6x-40)+(x+20)=180

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Solution for (180-3x)+(6x-40)+(x+20)=180 equation: 



(180-3x)+(6x-40)+(x+20)=180

We move all terms to the left:

(180-3x)+(6x-40)+(x+20)-(180)=0

We add all the numbers together, and all the variables

(-3x+180)+(6x-40)+(x+20)-180=0

We get rid of parentheses

-3x+6x+x+180-40+20-180=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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