(180-(6x+3)-(4x-3)+(9x+12))=180

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Solution for (180-(6x+3)-(4x-3)+(9x+12))=180 equation: 



(180-(6x+3)-(4x-3)+(9x+12))=180

We move all terms to the left:

(180-(6x+3)-(4x-3)+(9x+12))-(180)=0



We calculate terms in parentheses: +(180-(6x+3)-(4x-3)+(9x+12)), so:

180-(6x+3)-(4x-3)+(9x+12)

determiningTheFunctionDomain
-(6x+3)-(4x-3)+(9x+12)+180

We get rid of parentheses

-6x-4x+9x-3+3+12+180

We add all the numbers together, and all the variables

-1x+192

Back to the equation:

+(-1x+192)



We get rid of parentheses

-1x+192-180=0

We add all the numbers together, and all the variables

-1x+12=0

We move all terms containing x to the left, all other terms to the right

-x=-12

x=-12/-1

x=+12

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