(18-7x)+(42+10x)=149

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Solution for (18-7x)+(42+10x)=149 equation: 



(18-7x)+(42+10x)=149

We move all terms to the left:

(18-7x)+(42+10x)-(149)=0

We add all the numbers together, and all the variables

(-7x+18)+(10x+42)-149=0

We get rid of parentheses

-7x+10x+18+42-149=0

We add all the numbers together, and all the variables

3x-89=0

We move all terms containing x to the left, all other terms to the right

3x=89

x=89/3

x=29+2/3

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