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(18-6x)(2+3x)=0
We add all the numbers together, and all the variables
(-6x+18)(3x+2)=0
We multiply parentheses ..
(-18x^2-12x+54x+36)=0
We get rid of parentheses
-18x^2-12x+54x+36=0
We add all the numbers together, and all the variables
-18x^2+42x+36=0
a = -18; b = 42; c = +36;
Δ = b2-4ac
Δ = 422-4·(-18)·36
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-66}{2*-18}=\frac{-108}{-36} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+66}{2*-18}=\frac{24}{-36} =-2/3 $
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