(18+11)18=(c+14)c

Solution for (18+11)18=(c+14)c equation:

(18+11)18=(c+14)c

We move all terms to the left:

(18+11)18-((c+14)c)=0

We add all the numbers together, and all the variables

-((c+14)c)+2918=0


We calculate terms in parentheses: -((c+14)c), so:

(c+14)c

We multiply parentheses

c^2+14c

Back to the equation:

-(c^2+14c)


We get rid of parentheses

-c^2-14c+2918=0

We add all the numbers together, and all the variables

-1c^2-14c+2918=0

a = -1; b = -14; c = +2918;
Δ = b2-4ac
Δ = -142-4·(-1)·2918
Δ = 11868
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11868}=\sqrt{4*2967}=\sqrt{4}*\sqrt{2967}=2\sqrt{2967}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{2967}}{2*-1}=\frac{14-2\sqrt{2967}}{-2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{2967}}{2*-1}=\frac{14+2\sqrt{2967}}{-2}
$