(17-3x)+x+(x-2)+(x-1)=14

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Solution for (17-3x)+x+(x-2)+(x-1)=14 equation:


Simplifying
(17 + -3x) + x + (x + -2) + (x + -1) = 14

Remove parenthesis around (17 + -3x)
17 + -3x + x + (x + -2) + (x + -1) = 14

Reorder the terms:
17 + -3x + x + (-2 + x) + (x + -1) = 14

Remove parenthesis around (-2 + x)
17 + -3x + x + -2 + x + (x + -1) = 14

Reorder the terms:
17 + -3x + x + -2 + x + (-1 + x) = 14

Remove parenthesis around (-1 + x)
17 + -3x + x + -2 + x + -1 + x = 14

Reorder the terms:
17 + -2 + -1 + -3x + x + x + x = 14

Combine like terms: 17 + -2 = 15
15 + -1 + -3x + x + x + x = 14

Combine like terms: 15 + -1 = 14
14 + -3x + x + x + x = 14

Combine like terms: -3x + x = -2x
14 + -2x + x + x = 14

Combine like terms: -2x + x = -1x
14 + -1x + x = 14

Combine like terms: -1x + x = 0
14 + 0 = 14
14 = 14

Add '-14' to each side of the equation.
14 + -14 = 14 + -14

Combine like terms: 14 + -14 = 0
0 = 14 + -14

Combine like terms: 14 + -14 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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