(17(2-x)-5(x+12))/(1-7x)=8

Solution for (17(2-x)-5(x+12))/(1-7x)=8 equation:

(17(2-x)-5(x+12))/(1-7x)=8

We move all terms to the left:

(17(2-x)-5(x+12))/(1-7x)-(8)=0


Domain of the equation: (1-7x)!=0

We move all terms containing x to the left, all other terms to the right

-7x!=-1

x!=-1/-7

x!=1/7

x∈R


We add all the numbers together, and all the variables

(17(-1x+2)-5(x+12))/(-7x+1)-8=0

We multiply all the terms by the denominator


(17(-1x+2)-5(x+12))-8*(-7x+1)=0


We calculate terms in parentheses: +(17(-1x+2)-5(x+12)), so:

17(-1x+2)-5(x+12)

We multiply parentheses

-17x-5x+34-60

We add all the numbers together, and all the variables

-22x-26

Back to the equation:

+(-22x-26)


We multiply parentheses

(-22x-26)+56x-8=0

We get rid of parentheses

-22x+56x-26-8=0

We add all the numbers together, and all the variables

34x-34=0

We move all terms containing x to the left, all other terms to the right

34x=34

x=34/34

x=1