(16x12y-18)3/2

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Solution for (16x12y-18)3/2 equation:


x in (-oo:+oo)

((16*x^12*y-18)^3)/2 = 0

16*x^12*y = 18 // : 16*y

x^12 = (9*y^-1)/8

x^12 = (9*y^-1)/8 // ^ 1/12

abs(x) = (9^(1/12)*y^(-1/12))/(8^(1/12))

x = (9^(1/12)*y^(-1/12))/(8^(1/12)) or x = -((9^(1/12)*y^(-1/12))/(8^(1/12)))

x in { (9^(1/12)*y^(-1/12))/(8^(1/12)), -((9^(1/12)*y^(-1/12))/(8^(1/12))), (9^(1/12)*y^(-1/12))/(8^(1/12)), -((9^(1/12)*y^(-1/12))/(8^(1/12))), (9^(1/12)*y^(-1/12))/(8^(1/12)), -((9^(1/12)*y^(-1/12))/(8^(1/12))) }

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