(16x-79)=(10x+5)

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Solution for (16x-79)=(10x+5) equation: 



(16x-79)=(10x+5)

We move all terms to the left:

(16x-79)-((10x+5))=0

We get rid of parentheses

16x-((10x+5))-79=0



We calculate terms in parentheses: -((10x+5)), so:

(10x+5)

We get rid of parentheses

10x+5

Back to the equation:

-(10x+5)



We get rid of parentheses

16x-10x-5-79=0

We add all the numbers together, and all the variables

6x-84=0

We move all terms containing x to the left, all other terms to the right

6x=84

x=84/6

x=14

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