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(16x-5)=90+(5x+4)
We move all terms to the left:
(16x-5)-(90+(5x+4))=0
We get rid of parentheses
16x-(90+(5x+4))-5=0
We calculate terms in parentheses: -(90+(5x+4)), so:We get rid of parentheses
90+(5x+4)
determiningTheFunctionDomain (5x+4)+90
We get rid of parentheses
5x+4+90
We add all the numbers together, and all the variables
5x+94
Back to the equation:
-(5x+94)
16x-5x-94-5=0
We add all the numbers together, and all the variables
11x-99=0
We move all terms containing x to the left, all other terms to the right
11x=99
x=99/11
x=9
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