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(16x-5)(5x+4)=180
We move all terms to the left:
(16x-5)(5x+4)-(180)=0
We multiply parentheses ..
(+80x^2+64x-25x-20)-180=0
We get rid of parentheses
80x^2+64x-25x-20-180=0
We add all the numbers together, and all the variables
80x^2+39x-200=0
a = 80; b = 39; c = -200;
Δ = b2-4ac
Δ = 392-4·80·(-200)
Δ = 65521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-\sqrt{65521}}{2*80}=\frac{-39-\sqrt{65521}}{160} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+\sqrt{65521}}{2*80}=\frac{-39+\sqrt{65521}}{160} $
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