(16x-4)=3x+10x-20

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Solution for (16x-4)=3x+10x-20 equation: 



(16x-4)=3x+10x-20

We move all terms to the left:

(16x-4)-(3x+10x-20)=0

We add all the numbers together, and all the variables

(16x-4)-(13x-20)=0

We get rid of parentheses

16x-13x-4+20=0

We add all the numbers together, and all the variables

3x+16=0

We move all terms containing x to the left, all other terms to the right

3x=-16

x=-16/3

x=-5+1/3

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