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(16x-3)=(9x+8)
We move all terms to the left:
(16x-3)-((9x+8))=0
We get rid of parentheses
16x-((9x+8))-3=0
We calculate terms in parentheses: -((9x+8)), so:We get rid of parentheses
(9x+8)
We get rid of parentheses
9x+8
Back to the equation:
-(9x+8)
16x-9x-8-3=0
We add all the numbers together, and all the variables
7x-11=0
We move all terms containing x to the left, all other terms to the right
7x=11
x=11/7
x=1+4/7
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