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(16x+8)24x=320
We move all terms to the left:
(16x+8)24x-(320)=0
We multiply parentheses
384x^2+192x-320=0
a = 384; b = 192; c = -320;
Δ = b2-4ac
Δ = 1922-4·384·(-320)
Δ = 528384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{528384}=\sqrt{4096*129}=\sqrt{4096}*\sqrt{129}=64\sqrt{129}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(192)-64\sqrt{129}}{2*384}=\frac{-192-64\sqrt{129}}{768} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(192)+64\sqrt{129}}{2*384}=\frac{-192+64\sqrt{129}}{768} $
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