(16b-3)-5(3b+2)=-5

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Solution for (16b-3)-5(3b+2)=-5 equation: 



(16b-3)-5(3b+2)=-5

We move all terms to the left:

(16b-3)-5(3b+2)-(-5)=0

We add all the numbers together, and all the variables

(16b-3)-5(3b+2)+5=0

We multiply parentheses

(16b-3)-15b-10+5=0

We get rid of parentheses

16b-15b-3-10+5=0

We add all the numbers together, and all the variables

b-8=0

We move all terms containing b to the left, all other terms to the right

b=8

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