(16/x)=(x/9)

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Solution for (16/x)=(x/9) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

16/x = x/9 // - x/9

16/x-(x/9) = 0

16*x^-1-1/9*x^1 = 0

(16*x^0-1/9*x^2)/(x^1) = 0 // * x^2

x^1*(16*x^0-1/9*x^2) = 0

x^1

(-1/9)*x^2+16 = 0

(-1/9)*x^2+16 = 0

DELTA = 0^2-(4*16*(-1/9))

DELTA = 64/9

DELTA > 0

x = ((64/9)^(1/2)+0)/(2*(-1/9)) or x = (0-(64/9)^(1/2))/(2*(-1/9))

x = -12 or x = 12

x in { -12, 12} 

x in { -12, 12 }

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