(16/3)x=48

Solution for (16/3)x=48 equation:

(16/3)x=48

We move all terms to the left:

(16/3)x-(48)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+16/3)x-48=0

We multiply parentheses

16x^2-48=0

a = 16; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·16·(-48)
Δ = 3072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3072}=\sqrt{1024*3}=\sqrt{1024}*\sqrt{3}=32\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{3}}{2*16}=\frac{0-32\sqrt{3}}{32}
=-\frac{32\sqrt{3}}{32}
=-\sqrt{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{3}}{2*16}=\frac{0+32\sqrt{3}}{32}
=\frac{32\sqrt{3}}{32}
=\sqrt{3}
$