(16-x)+(3x)=40

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Solution for (16-x)+(3x)=40 equation: 



(16-x)+(3x)=40

We move all terms to the left:

(16-x)+(3x)-(40)=0

We add all the numbers together, and all the variables

(-1x+16)+3x-40=0

We add all the numbers together, and all the variables

3x+(-1x+16)-40=0

We get rid of parentheses

3x-1x+16-40=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12

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